Model scale in lengths, areas and volumes
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Log in to continueConnect a length ratio to the dimension of the measurement being compared.
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A model’s length is 4 cm. An enlargement multiplies all lengths by 3. What is the new length?
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Answer: 12 cm
- Apply the length scale factor once.
- 4 × 3 = 12 cm.
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Curriculum reference
Victorian Curriculum F–10 Version 2.0
Pi Leo practice scope
Connect a length ratio to the dimension of the measurement being compared.
Read the official VCAA curriculum description (VC2M7M06)
These quizzes practise concepts within this topic. Multiple-choice answers alone do not demonstrate drawing, conducting an investigation or using a digital tool.
Activities to practise beyond the quiz
- Supported by the guided activity; selecting an MCQ does not demonstrate this action.
- VC2M7M06-C01For similar objects, every corresponding length is multiplied by the same scale factor.
- VC2M7M06-C02When both length directions are multiplied by k, area is multiplied by k². It does not simply grow by k.
- VC2M7M06-C03Three independent length directions give a volume factor of k³ for similar solids.
- VC2M7M06-C04Formulating, interpreting and communicating a practical ratio model for lengths, areas and volumes.
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Descriptor-derived subskills
- D01Apply a length scale factorFor similar objects, every corresponding length is multiplied by the same scale factor.
- D02Account for two dimensionsWhen both length directions are multiplied by k, area is multiplied by k². It does not simply grow by k.
- D03Account for three dimensionsThree independent length directions give a volume factor of k³ for similar solids.