VC2M7M06 Official strand: Measurement

Model scale in lengths, areas and volumes

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Connect a length ratio to the dimension of the measurement being compared.

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A model’s length is 4 cm. An enlargement multiplies all lengths by 3. What is the new length?

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Answer: 12 cm

  1. Apply the length scale factor once.
  2. 4 × 3 = 12 cm.

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Curriculum reference

Victorian Curriculum F–10 Version 2.0

Pi Leo practice scope

Connect a length ratio to the dimension of the measurement being compared.

Read the official VCAA curriculum description (VC2M7M06)

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Activities to practise beyond the quiz

  • Supported by the guided activity; selecting an MCQ does not demonstrate this action.
  1. VC2M7M06-C01For similar objects, every corresponding length is multiplied by the same scale factor.
  2. VC2M7M06-C02When both length directions are multiplied by k, area is multiplied by k². It does not simply grow by k.
  3. VC2M7M06-C03Three independent length directions give a volume factor of k³ for similar solids.
  4. VC2M7M06-C04Formulating, interpreting and communicating a practical ratio model for lengths, areas and volumes.

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Subskills

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Descriptor-derived subskills

  1. D01
    Apply a length scale factorFor similar objects, every corresponding length is multiplied by the same scale factor.
  2. D02
    Account for two dimensionsWhen both length directions are multiplied by k, area is multiplied by k². It does not simply grow by k.
  3. D03
    Account for three dimensionsThree independent length directions give a volume factor of k³ for similar solids.
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